What is the answer to sqrt(x^2-2x+1)=x-1 ?

The answer to sqrt(x^2-2x+1)=x-1 is x>= 1

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sqrt(x^2-2x+1)=x-1

x^{2} - 2 x + 1 = x - 1

x \geq 1

Solution steps

x^{2} - 2 x + 1 = x - 1

Square both sides:

x^{2} - 2 x + 1 = x^{2} - 2 x + 1

x^{2} - 2 x + 1 = x^{2} - 2 x + 1

Both sides are equal

True for all x

Verify Solutions:

x < 1

False

, x = 1

True

, x > 1

True

The solution is

x \geq 1

3 - y - 6 = 0

1 + x^{2} = 5 - x^{2}

x = 12 - x

x^{\frac{1}{2}} = 2 x - 15

What is the answer to sqrt(x^2-2x+1)=x-1 ?
The answer to sqrt(x^2-2x+1)=x-1 is x>= 1
Solve for x: sqrt(x^2-2x+1)=x-1
The solution is x>= 1