What is the answer to sqrt(x^2+x-4)=2 ?

The answer to sqrt(x^2+x-4)=2 is x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2

Solve for x: sqrt(x^2+x-4)=2

The solution is x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2

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x^{2} + x - 4 = 2

x = \frac{- 1 + 33}{2}, x = \frac{- 1 - 33}{2}

Decimal Notation

x = 2.37228 \dots, x = - 3.37228 \dots

Solution steps

x^{2} + x - 4 = 2

Square both sides:

x^{2} + x - 4 = 4

x^{2} + x - 4 = 4

Solve

x^{2} + x - 4 = 4 : x = \frac{- 1 + 33}{2}, x = \frac{- 1 - 33}{2}

x = \frac{- 1 + 33}{2}, x = \frac{- 1 - 33}{2}

Verify Solutions:

x = \frac{- 1 + 33}{2}

True

, x = \frac{- 1 - 33}{2}

True

The solutions are

x = \frac{- 1 + 33}{2}, x = \frac{- 1 - 33}{2}

2 x + 2 4 x + 1 = 10

x - 1 = x^{2} + 5

2 = 1 - x

3 m^{2} + (m + 3)^{2} = 9

5 x^{2} - 6 x = 5 x - 6

What is the answer to sqrt(x^2+x-4)=2 ?
The answer to sqrt(x^2+x-4)=2 is x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2
Solve for x: sqrt(x^2+x-4)=2
The solution is x=(-1+sqrt(33))/2 ,x=(-1-sqrt(33))/2