What is the answer to \sqrt[4]{25}=\sqrt[4]{x^4} ?

The answer to \sqrt[4]{25}=\sqrt[4]{x^4} is x=sqrt(5),x=-sqrt(5)

Solve for x: \sqrt[4]{25}=\sqrt[4]{x^4}

The solution is x=sqrt(5),x=-sqrt(5)

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x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

Take both sides of the equation to the power of

4 : 25 = x^{4}

25 = x^{4}

Solve

25 = x^{4} : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

True

The solutions are

x = 5, x = - 5

y + 7 = 4 y + 13

4 x^{2} = 2 x

x^{2} + 33 x = 3

2 x - 11 x + 12 = 0

14.8 = (225 - x)^{0.5}

What is the answer to \sqrt[4]{25}=\sqrt[4]{x^4} ?
The answer to \sqrt[4]{25}=\sqrt[4]{x^4} is x=sqrt(5),x=-sqrt(5)
Solve for x: \sqrt[4]{25}=\sqrt[4]{x^4}
The solution is x=sqrt(5),x=-sqrt(5)