What is the answer to sqrt(x^2+33)x=3 ?

The answer to sqrt(x^2+33)x=3 is x=sqrt((-33+15\sqrt{5))/2}

Solve for x: sqrt(x^2+33)x=3

The solution is x=sqrt((-33+15\sqrt{5))/2}

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x^{2} + 33 x = 3

x = \frac{- 33 + 15 5}{2}

Decimal Notation

x = 0.52010 \dots

Solution steps

x^{2} + 33 x = 3

Square both sides:

x^{4} + 33 x^{2} = 9

x^{4} + 33 x^{2} = 9

Solve

x^{4} + 33 x^{2} = 9 : x = \frac{- 33 + 15 5}{2}, x = - \frac{- 33 + 15 5}{2}

x = \frac{- 33 + 15 5}{2}, x = - \frac{- 33 + 15 5}{2}

Verify Solutions:

x = \frac{- 33 + 15 5}{2}

True

, x = - \frac{- 33 + 15 5}{2}

False

The solution is

x = \frac{- 33 + 15 5}{2}

2 x - 11 x + 12 = 0

14.8 = (225 - x)^{0.5}

(5 x + 2)^{\frac{4}{3}} = 256

9 y + 4 - y + 4 = 4

What is the answer to sqrt(x^2+33)x=3 ?
The answer to sqrt(x^2+33)x=3 is x=sqrt((-33+15\sqrt{5))/2}
Solve for x: sqrt(x^2+33)x=3
The solution is x=sqrt((-33+15\sqrt{5))/2}