What is the answer to solvefor y,x=-sqrt(1-y) ?

The answer to solvefor y,x=-sqrt(1-y) is y=1-x^2 {x<= 0}

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solvefor y,x=-sqrt(1-y)

solve for

y, x = - 1 - y

y = 1 - x^{2} {x \leq 0}

Solution steps

x = - 1 - y

Divide both sides by

- 1

\frac{x}{- 1} = \frac{- 1 - y}{- 1}

Simplify

- x = 1 - y

Square both sides:

x^{2} = 1 - y

x^{2} = 1 - y

Solve

x^{2} = 1 - y : y = 1 - x^{2}

y = 1 - x^{2}

Verify Solutions:

y = 1 - x^{2} {x \leq 0}

The solution is

y = 1 - x^{2} {x \leq 0}

d, q = F d + 4

x + 2 x - 3 = 0

x^{\frac{4}{3}} = 9

y, x = 2 3 - y

x^{2} - 2 5 x + 5 = 0

What is the answer to solvefor y,x=-sqrt(1-y) ?
The answer to solvefor y,x=-sqrt(1-y) is y=1-x^2 {x<= 0}