What is the answer to 2+sqrt(36+x)=sqrt(16-2x) ?

The answer to 2+sqrt(36+x)=sqrt(16-2x) is x=-128/9

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2+sqrt(36+x)=sqrt(16-2x)

2 + 36 + x = 16 - 2 x

x = - \frac{128}{9}

Decimal Notation

x = - 14.22222 \dots

Solution steps

2 + 36 + x = 16 - 2 x

Remove square roots

576 + 16 x = 9 x^{2} + 144 x + 576

Solve

576 + 16 x = 9 x^{2} + 144 x + 576 : x = 0, x = - \frac{128}{9}

x = 0, x = - \frac{128}{9}

Verify Solutions:

x = 0

False

, x = - \frac{128}{9}

True

The solution is

x = - \frac{128}{9}

- 1 - 2 p + 10 = 11

2 = x + 9 + 2 x + 17

t, x = - t + 1

x - 1 = 6

What is the answer to 2+sqrt(36+x)=sqrt(16-2x) ?
The answer to 2+sqrt(36+x)=sqrt(16-2x) is x=-128/9
Solve for x: 2+sqrt(36+x)=sqrt(16-2x)
The solution is x=-128/9