What is the answer to sqrt(x^2-3x+2)=x+1 ?

The answer to sqrt(x^2-3x+2)=x+1 is x= 1/5

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sqrt(x^2-3x+2)=x+1

x^{2} - 3 x + 2 = x + 1

x = \frac{1}{5}

Decimal Notation

x = 0.2

Solution steps

x^{2} - 3 x + 2 = x + 1

Square both sides:

x^{2} - 3 x + 2 = x^{2} + 2 x + 1

x^{2} - 3 x + 2 = x^{2} + 2 x + 1

Solve

x^{2} - 3 x + 2 = x^{2} + 2 x + 1 : x = \frac{1}{5}

x = \frac{1}{5}

Verify Solutions:

x = \frac{1}{5}

True

The solution is

x = \frac{1}{5}

x, x = y

0 = (x + 1) x^{2} + 1

(2 x + 2)^{\frac{1}{4}} + 1 = 3

3 x - 1 + x + 4 = 3

What is the answer to sqrt(x^2-3x+2)=x+1 ?
The answer to sqrt(x^2-3x+2)=x+1 is x= 1/5
Solve for x: sqrt(x^2-3x+2)=x+1
The solution is x= 1/5