What is the answer to \sqrt[3]{2x}=(x^2)/8 ?

The answer to \sqrt[3]{2x}=(x^2)/8 is x=0,x=4

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\sqrt[3]{2x}=(x^2)/8

x = 0, x = 4

Solution steps

Multiply both sides by

8

Simplify

Take both sides of the equation to the power of

3 : 1024 x = x^{6}

1024 x = x^{6}

Solve

1024 x = x^{6} : x = 0, x = 4

x = 0, x = 4

Verify Solutions:

x = 0

True

, x = 4

True

The solutions are

x = 0, x = 4

x + 3 + x + 2 = 5

y = 1 - y^{2}

2 {x + 1} + x = 7

\frac{1}{x} = 2 b

x - 2 = - 4 + x

What is the answer to \sqrt[3]{2x}=(x^2)/8 ?
The answer to \sqrt[3]{2x}=(x^2)/8 is x=0,x=4
Solve for x: \sqrt[3]{2x}=(x^2)/8
The solution is x=0,x=4