What is the answer to n^{(-2)/3}=9 ?

The answer to n^{(-2)/3}=9 is n=sqrt(1/729),n=-sqrt(1/729)

Solve for n: n^{(-2)/3}=9

The solution is n=sqrt(1/729),n=-sqrt(1/729)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{\frac{- 2}{3}} = 9

n = \frac{1}{729}, n = - \frac{1}{729}

Decimal Notation

n = 0.03703 \dots, n = - 0.03703 \dots

Solution steps

n^{\frac{- 2}{3}} = 9

Take both sides of the equation to the power of

- 3 : n^{2} = \frac{1}{729}

n^{2} = \frac{1}{729}

Solve

n^{2} = \frac{1}{729} : n = \frac{1}{729}, n = - \frac{1}{729}

n = \frac{1}{729}, n = - \frac{1}{729}

Verify Solutions:

n = \frac{1}{729}

True

, n = - \frac{1}{729}

True

The solutions are

n = \frac{1}{729}, n = - \frac{1}{729}

v - 4 = 7

x^{(\frac{( 4 )}{( 9 )})} = 16

1100 = 1087 \frac{T}{273}

x + 15 = 3 x - 3

4 x^{2} - 4 x + 1 + (x + 4) = x + 7

What is the answer to n^{(-2)/3}=9 ?
The answer to n^{(-2)/3}=9 is n=sqrt(1/729),n=-sqrt(1/729)
Solve for n: n^{(-2)/3}=9
The solution is n=sqrt(1/729),n=-sqrt(1/729)