What is the answer to 6+\sqrt[3]{3x^2}=18 ?

The answer to 6+\sqrt[3]{3x^2}=18 is x=24,x=-24

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6+\sqrt[3]{3x^2}=18

x = 24, x = - 24

Solution steps

Move

6

to the right side

Take both sides of the equation to the power of

3 : 3 x^{2} = 1728

3 x^{2} = 1728

Solve

3 x^{2} = 1728 : x = 24, x = - 24

x = 24, x = - 24

Verify Solutions:

x = 24

True

, x = - 24

True

The solutions are

x = 24, x = - 24

(4 x + 4)^{\frac{1}{3}} = 2

0 = - 2 \cdot 20 \cdot t + 144

y^{0.3} (2 y + 4) = 8 y

(2 x + 3)^{2} + 3 - 1 = 1

What is the answer to 6+\sqrt[3]{3x^2}=18 ?
The answer to 6+\sqrt[3]{3x^2}=18 is x=24,x=-24
Solve for x: 6+\sqrt[3]{3x^2}=18
The solution is x=24,x=-24