What is the answer to \sqrt[5]{2x-3}=-1 ?

The answer to \sqrt[5]{2x-3}=-1 is x=1

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\sqrt[5]{2x-3}=-1

x = 1

Solution steps

Take both sides of the equation to the power of

5 : 2 x - 3 = - 1

2 x - 3 = - 1

Solve

2 x - 3 = - 1 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

2 x - 1 = 3 x - 6

w^{2} - 5 + w = \frac{1 + 6}{w}

5 = 10 (0.38)^{0.2} K^{0.4}

x - 5 - 16 x = 0

(\frac{x}{1 - x})^{0.88} = 0.536

What is the answer to \sqrt[5]{2x-3}=-1 ?
The answer to \sqrt[5]{2x-3}=-1 is x=1
Solve for x: \sqrt[5]{2x-3}=-1
The solution is x=1