What is the answer to solvefor x,y=2sqrt(x)+1 ?

The answer to solvefor x,y=2sqrt(x)+1 is x=(y^2)/4-y/2+1/4 {y>= 1}

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solvefor x,y=2sqrt(x)+1

solve for

x, y = 2 x + 1

x = \frac{y ^{2}}{4} - \frac{y}{2} + \frac{1}{4} {y \geq 1}

Solution steps

y = 2 x + 1

Switch sides

2 x + 1 = y

Move

1

to the right side

2 x = y - 1

Divide both sides by

2

x = \frac{y - 1}{2}

Square both sides:

x = \frac{y ^{2}}{4} - \frac{y}{2} + \frac{1}{4}

x = \frac{y ^{2}}{4} - \frac{y}{2} + \frac{1}{4}

Verify Solutions:

x = \frac{y ^{2}}{4} - \frac{y}{2} + \frac{1}{4} {y \geq 1}

The solution is

x = \frac{y ^{2}}{4} - \frac{y}{2} + \frac{1}{4} {y \geq 1}

x + 3 + 6 - 5 x + 3 = 0

3 x - 16 x + 5 = 0

3 x - 1 = 2 x + 4

x - x - 2 = 1

What is the answer to solvefor x,y=2sqrt(x)+1 ?
The answer to solvefor x,y=2sqrt(x)+1 is x=(y^2)/4-y/2+1/4 {y>= 1}