What is the answer to solvefor y,x=3sqrt(4y-1) ?

The answer to solvefor y,x=3sqrt(4y-1) is y=(x^2+9)/(36) {x>= 0}

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solvefor y,x=3sqrt(4y-1)

solve for

y, x = 3 4 y - 1

y = \frac{x ^{2} + 9}{36} {x \geq 0}

Solution steps

x = 3 4 y - 1

Switch sides

3 4 y - 1 = x

Divide both sides by

3

4 y - 1 = \frac{x}{3}

Square both sides:

4 y - 1 = \frac{x ^{2}}{9}

4 y - 1 = \frac{x ^{2}}{9}

Solve

4 y - 1 = \frac{x ^{2}}{9} : y = \frac{x ^{2} + 9}{36}

y = \frac{x ^{2} + 9}{36}

Verify Solutions:

y = \frac{x ^{2} + 9}{36} {x \geq 0}

The solution is

y = \frac{x ^{2} + 9}{36} {x \geq 0}

9 = (0 + 6)^{2} + (y - 4)^{2}

7 x + 57 = 2 x + 6

4 x^{2} - 4 x + 1 + (x + 4) = a + 7

7 x + 8 = x + 2

What is the answer to solvefor y,x=3sqrt(4y-1) ?
The answer to solvefor y,x=3sqrt(4y-1) is y=(x^2+9)/(36) {x>= 0}