What is the answer to 3x=(4-x^2)^{1/2} ?

The answer to 3x=(4-x^2)^{1/2} is x=sqrt(2/5)

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3x=(4-x^2)^{1/2}

3 x = (4 - x^{2})^{\frac{1}{2}}

x = \frac{2}{5}

Decimal Notation

x = 0.63245 \dots

Solution steps

3 x = (4 - x^{2})^{\frac{1}{2}}

Square both sides:

9 x^{2} = 4 - x^{2}

9 x^{2} = 4 - x^{2}

Solve

9 x^{2} = 4 - x^{2} : x = \frac{2}{5}, x = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

Verify Solutions:

x = \frac{2}{5}

True

, x = - \frac{2}{5}

False

The solution is

x = \frac{2}{5}

2 x = 4 x + 9 - 3

x - 5 + 2 = 7

2 s + 4 = - \frac{1}{2} - s

x - 8 - 7 x = 0

y, x = 8 y - y^{2}

What is the answer to 3x=(4-x^2)^{1/2} ?
The answer to 3x=(4-x^2)^{1/2} is x=sqrt(2/5)
Solve for x: 3x=(4-x^2)^{1/2}
The solution is x=sqrt(2/5)