What is the answer to 3=sqrt(2^2+x^2) ?

The answer to 3=sqrt(2^2+x^2) is x=sqrt(5),x=-sqrt(5)

Solve for x: 3=sqrt(2^2+x^2)

The solution is x=sqrt(5),x=-sqrt(5)

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3 = 2^{2} + x^{2}

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

3 = 2^{2} + x^{2}

Square both sides:

9 = 4 + x^{2}

9 = 4 + x^{2}

Solve

9 = 4 + x^{2} : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

True

The solutions are

x = 5, x = - 5

0 = x + x - 6

x, 2 x y = 1

2 \cdot x - 1 + x + 3 = 2

4 y + 13 = 6 y + 7

x - 3 = 13 x + 9

What is the answer to 3=sqrt(2^2+x^2) ?
The answer to 3=sqrt(2^2+x^2) is x=sqrt(5),x=-sqrt(5)
Solve for x: 3=sqrt(2^2+x^2)
The solution is x=sqrt(5),x=-sqrt(5)