What is the answer to solvefor t,x=4+sqrt(8t+4) ?

The answer to solvefor t,x=4+sqrt(8t+4) is t=(x^2-8x+12)/8 {x>= 4}

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solvefor t,x=4+sqrt(8t+4)

solve for

t, x = 4 + 8 t + 4

t = \frac{x ^{2} - 8 x + 12}{8} {x \geq 4}

Solution steps

x = 4 + 8 t + 4

Switch sides

4 + 8 t + 4 = x

Move

4

to the right side

8 t + 4 = x - 4

Square both sides:

8 t + 4 = x^{2} - 8 x + 16

8 t + 4 = x^{2} - 8 x + 16

Solve

8 t + 4 = x^{2} - 8 x + 16 : t = \frac{x ^{2} - 8 x + 12}{8}

t = \frac{x ^{2} - 8 x + 12}{8}

Verify Solutions:

t = \frac{x ^{2} - 8 x + 12}{8} {x \geq 4}

The solution is

t = \frac{x ^{2} - 8 x + 12}{8} {x \geq 4}

4 = x + 2 x - 7

1 - x^{2} = a x

x = 5 + (3 x - 11)^{\frac{1}{2}}

3 x - 7 = 5 x + 5

What is the answer to solvefor t,x=4+sqrt(8t+4) ?
The answer to solvefor t,x=4+sqrt(8t+4) is t=(x^2-8x+12)/8 {x>= 4}