What is the answer to solvefor x,sqrt(3x^2-4)=x+5 ?

The answer to solvefor x,sqrt(3x^2-4)=x+5 is x=-(-5+sqrt(83))/2 ,x=(5+sqrt(83))/2

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solvefor x,sqrt(3x^2-4)=x+5

x, 3 x^{2} - 4 = x + 5

x = - \frac{- 5 + 83}{2}, x = \frac{5 + 83}{2}

Decimal Notation

x = - 2.05521 \dots, x = 7.05521 \dots

Solution steps

3 x^{2} - 4 = x + 5

Square both sides:

3 x^{2} - 4 = x^{2} + 10 x + 25

3 x^{2} - 4 = x^{2} + 10 x + 25

Solve

3 x^{2} - 4 = x^{2} + 10 x + 25 : x = - \frac{- 5 + 83}{2}, x = \frac{5 + 83}{2}

x = - \frac{- 5 + 83}{2}, x = \frac{5 + 83}{2}

Verify Solutions:

x = - \frac{- 5 + 83}{2}

True

, x = \frac{5 + 83}{2}

True

The solutions are

x = - \frac{- 5 + 83}{2}, x = \frac{5 + 83}{2}

10 0^{2} + (x)^{2} = 106.9

x - 4^{4} x - 5 = 0

4 x^{2} + x + 4 = 13

2 x = 24

3 x - 1 = 0

What is the answer to solvefor x,sqrt(3x^2-4)=x+5 ?
The answer to solvefor x,sqrt(3x^2-4)=x+5 is x=-(-5+sqrt(83))/2 ,x=(5+sqrt(83))/2