What is the answer to 5=sqrt((-1-2)^2+(-2-y)^2) ?

The answer to 5=sqrt((-1-2)^2+(-2-y)^2) is y=2,y=-6

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5=sqrt((-1-2)^2+(-2-y)^2)

5 = (- 1 - 2)^{2} + (- 2 - y)^{2}

y = 2, y = - 6

Solution steps

5 = (- 1 - 2)^{2} + (- 2 - y)^{2}

Square both sides:

25 = y^{2} + 4 y + 13

25 = y^{2} + 4 y + 13

Solve

25 = y^{2} + 4 y + 13 : y = 2, y = - 6

y = 2, y = - 6

Verify Solutions:

y = 2

True

, y = - 6

True

The solutions are

y = 2, y = - 6

8 (2 x + 9)^{\frac{1}{4}} = 24

4 x + 5 = x

2 x + 27 - 4 = 1

- 4 u + 1 + 2 u + 4 = 3

(- 3 - 1)^{2} + (- 2 - y)^{2} = 5

What is the answer to 5=sqrt((-1-2)^2+(-2-y)^2) ?
The answer to 5=sqrt((-1-2)^2+(-2-y)^2) is y=2,y=-6
Solve for y: 5=sqrt((-1-2)^2+(-2-y)^2)
The solution is y=2,y=-6