What is the answer to sqrt(x^2-x-1)=x+4 ?

The answer to sqrt(x^2-x-1)=x+4 is x=-17/9

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sqrt(x^2-x-1)=x+4

x^{2} - x - 1 = x + 4

x = - \frac{17}{9}

Decimal Notation

x = - 1.88888 \dots

Solution steps

x^{2} - x - 1 = x + 4

Square both sides:

x^{2} - x - 1 = x^{2} + 8 x + 16

x^{2} - x - 1 = x^{2} + 8 x + 16

Solve

x^{2} - x - 1 = x^{2} + 8 x + 16 : x = - \frac{17}{9}

x = - \frac{17}{9}

Verify Solutions:

x = - \frac{17}{9}

True

The solution is

x = - \frac{17}{9}

x^{2} - x - 1 = x + 3

731093 = 525600 e^{0.03}

(\frac{x}{1 - x})^{- 0.93} = 1.118

What is the answer to sqrt(x^2-x-1)=x+4 ?
The answer to sqrt(x^2-x-1)=x+4 is x=-17/9
Solve for x: sqrt(x^2-x-1)=x+4
The solution is x=-17/9