What is the answer to sqrt(x^2-9)-sqrt(4x-12)=0 ?

The answer to sqrt(x^2-9)-sqrt(4x-12)=0 is x=3

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sqrt(x^2-9)-sqrt(4x-12)=0

x^{2} - 9 - 4 x - 12 = 0

x = 3

Solution steps

x^{2} - 9 - 4 x - 12 = 0

Remove square roots

x^{2} - 9 = 4 x - 12

Solve

x^{2} - 9 = 4 x - 12 : x = 3, x = 1

x = 3, x = 1

Verify Solutions:

x = 3

True

, x = 1

False

The solution is

x = 3

0 = 1 + x \cdot x

2 x + 5 + 6 = 3 x + 3

3 = (x - 7)^{2} + (1 - 1)^{2}

10 100 - y = 60 y - 300

23 = u^{1} + u^{2}

What is the answer to sqrt(x^2-9)-sqrt(4x-12)=0 ?
The answer to sqrt(x^2-9)-sqrt(4x-12)=0 is x=3
Solve for x: sqrt(x^2-9)-sqrt(4x-12)=0
The solution is x=3