What is the answer to solvefor x,y=sqrt(x+y) ?

The answer to solvefor x,y=sqrt(x+y) is x=y^2-y {y>= 0}

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solvefor x,y=sqrt(x+y)

solve for

x, y = x + y

x = y^{2} - y {y \geq 0}

Solution steps

y = x + y

Square both sides:

y^{2} = x + y

y^{2} = x + y

Solve

y^{2} = x + y : x = y^{2} - y

x = y^{2} - y

Verify Solutions:

x = y^{2} - y {y \geq 0}

The solution is

x = y^{2} - y {y \geq 0}

x^{2} + 33 - x = 3

2 x - 5 = x + 9

(12 \cdot x)^{0.5} = 12

9 - 2 X = X^{2} + 9

y^{\frac{2}{3}} - \frac{1}{49} = 0

What is the answer to solvefor x,y=sqrt(x+y) ?
The answer to solvefor x,y=sqrt(x+y) is x=y^2-y {y>= 0}