What is the answer to j(x)=((3x))/((sqrt(x+4))) ?

The answer to j(x)=((3x))/((sqrt(x+4))) is x=0,x= 9/(j^2)-4 {j=-3/2 \lor j>= 0}

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j(x)=((3x))/((sqrt(x+4)))

j (x) = \frac{( 3 x )}{( x + 4 )}

x = 0, x = \frac{9}{j ^{2}} - 4 {j = - \frac{3}{2} or j \geq 0}

Solution steps

j (x) = \frac{( 3 x )}{( x + 4 )}

Multiply both sides by

x + 4

j x x + 4 = \frac{3 x}{x + 4} x + 4

Simplify

j x x + 4 = 3 x

Move

3 x

to the left side

j x x + 4 - 3 x = 0

Factor

j x x + 4 - 3 x : x (j x + 4 - 3)

x (j x + 4 - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or j x + 4 - 3 = 0

Solve

j x + 4 - 3 = 0 : x = \frac{9}{j ^{2}} - 4

x = 0, x = \frac{9}{j ^{2}} - 4

Verify Solutions:

x = 0

True

, x = \frac{9}{j ^{2}} - 4 {j = - \frac{3}{2} or j \geq 0}

The solutions are

x = 0, x = \frac{9}{j ^{2}} - 4 {j = - \frac{3}{2} or j \geq 0}

6 r = r^{2} - 16

3 x - 1 - x - 1 = 2

2 t + 6 = - 4

\frac{2 p + 6}{4} = 3

x^{4} - 2 x^{2} + 1 = x - 1

What is the answer to j(x)=((3x))/((sqrt(x+4))) ?
The answer to j(x)=((3x))/((sqrt(x+4))) is x=0,x= 9/(j^2)-4 {j=-3/2 \lor j>= 0}