What is the answer to (sqrt(2x+1))^2=(x+1)^2 ?

The answer to (sqrt(2x+1))^2=(x+1)^2 is x=0

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(sqrt(2x+1))^2=(x+1)^2

(2 x + 1)^{2} = (x + 1)^{2}

x = 0

Solution steps

(2 x + 1)^{2} = (x + 1)^{2}

Rewrite the equation with

2 x + 1 = u

and

x = \frac{u ^{2} - 1}{2}

u^{2} = ((\frac{u ^{2} - 1}{2}) + 1)^{2}

Solve

u^{2} = ((\frac{u ^{2} - 1}{2}) + 1)^{2} : u = 1, u = - 1

u = 1, u = - 1

Substitute back

u = 2 x + 1,

solve for

x

Solve

2 x + 1 = 1 : x = 0

Solve

2 x + 1 = - 1 :

No Solution for

x \in R

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

- 1 = - n + 4 n + 17

1 + x = (x - 1)^{2}

y + 5 = 0

u, u + v = 5

What is the answer to (sqrt(2x+1))^2=(x+1)^2 ?
The answer to (sqrt(2x+1))^2=(x+1)^2 is x=0
Solve for x: (sqrt(2x+1))^2=(x+1)^2
The solution is x=0