What are the solutions to the equation (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0 ?

The solutions to the equation (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0 are

Find the zeros of (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0

The zeros of (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0 are

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Solution steps

Expand

Write in the standard form

a x^{2} + b x + c = 0

Solve with the quadratic formula

Simplify

Separate the solutions

The solutions to the quadratic equation are:

- 3 x^{2} - 12 x - 12 = 0

3 (x + 3) = 18

- 4 x - 8 > - 20

\frac{8}{3}

\frac{a ^{6} b ^{5} c ^{3}}{a ^{5} b ^{2} c ^{3}}

What are the solutions to the equation (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0 ?
The solutions to the equation (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0 are
Find the zeros of (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0
The zeros of (x+4)^2+(x+4)\sqrt[3]{7}+\sqrt[3]{49}=0 are