What is the answer to solvefor X,sqrt(2X)+Y=pi ?

The answer to solvefor X,sqrt(2X)+Y=pi is X=(pi^2-2piY+Y^2)/2 {Y<= pi}

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solvefor X,sqrt(2X)+Y=pi

solve for

X, 2 X + Y = π

X = \frac{π ^{2} - 2 πY + Y ^{2}}{2} {Y \leq π}

Solution steps

2 X + Y = π

Move

Y

to the right side

2 X = π - Y

Square both sides:

2 X = π^{2} - 2 πY + Y^{2}

2 X = π^{2} - 2 πY + Y^{2}

Solve

2 X = π^{2} - 2 πY + Y^{2} : X = \frac{π ^{2} - 2 πY + Y ^{2}}{2}

X = \frac{π ^{2} - 2 πY + Y ^{2}}{2}

Verify Solutions:

X = \frac{π ^{2} - 2 πY + Y ^{2}}{2} {Y \leq π}

The solution is

X = \frac{π ^{2} - 2 πY + Y ^{2}}{2} {Y \leq π}

x = 3 + 2 x

9 = x - 2

\frac{0.05}{n} = 0.001

4 x + 76 = 10

x, f (m - 2) = 2 - x

What is the answer to solvefor X,sqrt(2X)+Y=pi ?
The answer to solvefor X,sqrt(2X)+Y=pi is X=(pi^2-2piY+Y^2)/2 {Y<= pi}