What is the answer to solvefor x,f(m-2)=sqrt(2-x) ?

The answer to solvefor x,f(m-2)=sqrt(2-x) is x=2-f^2m^2+4f^2m-4f^2

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solvefor x,f(m-2)=sqrt(2-x)

solve for

x, f (m - 2) = 2 - x

x = 2 - f^{2} m^{2} + 4 f^{2} m - 4 f^{2}

Solution steps

f (m - 2) = 2 - x

Square both sides:

f^{2} m^{2} - 4 f^{2} m + 4 f^{2} = 2 - x

f^{2} m^{2} - 4 f^{2} m + 4 f^{2} = 2 - x

Solve

f^{2} m^{2} - 4 f^{2} m + 4 f^{2} = 2 - x : x = 2 - f^{2} m^{2} + 4 f^{2} m - 4 f^{2}

x = 2 - f^{2} m^{2} + 4 f^{2} m - 4 f^{2}

2 x = 1 - x + 7

2 x + 6 - 4 - 4 x = - 4

5 x - 9 = 5 x - 3

x, (x^{2} + a) = 2 x

2 x - 1 - 4 x - 2 = 0

What is the answer to solvefor x,f(m-2)=sqrt(2-x) ?
The answer to solvefor x,f(m-2)=sqrt(2-x) is x=2-f^2m^2+4f^2m-4f^2