What is the answer to solvefor x,sqrt((x^2+a))=2x ?

The answer to solvefor x,sqrt((x^2+a))=2x is x=sqrt(a/3) {a>= 0},x=-sqrt(a/3) {a=0}

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solvefor x,sqrt((x^2+a))=2x

x, (x^{2} + a) = 2 x

x = \frac{a}{3} {a \geq 0}, x = - \frac{a}{3} {a = 0}

Solution steps

(x^{2} + a) = 2 x

Square both sides:

x^{2} + a = 4 x^{2}

x^{2} + a = 4 x^{2}

Solve

x^{2} + a = 4 x^{2} : x = \frac{a}{3}, x = - \frac{a}{3}

x = \frac{a}{3}, x = - \frac{a}{3}

Verify Solutions:

x = \frac{a}{3} {a \geq 0}, x = - \frac{a}{3} {a = 0}

The solutions are

x = \frac{a}{3} {a \geq 0}, x = - \frac{a}{3} {a = 0}

2 x - 1 - 4 x - 2 = 0

15 - 17 x = x + 9

1 - 16 x^{2} = 0

\frac{ψ}{ψ ^{2} + 1} = 1 - ψ

What is the answer to solvefor x,sqrt((x^2+a))=2x ?
The answer to solvefor x,sqrt((x^2+a))=2x is x=sqrt(a/3) {a>= 0},x=-sqrt(a/3) {a=0}