What is the answer to solvefor x,sqrt(x^2)+x+y=10 ?

The answer to solvefor x,sqrt(x^2)+x+y=10 is x=-(y-10)/2 {y<= 10}

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solvefor x,sqrt(x^2)+x+y=10

solve for

x, x^{2} + x + y = 10

x = - \frac{y - 10}{2} {y \leq 10}

Solution steps

x^{2} + x + y = 10

Remove square roots

x^{2} = 2 x y - 20 y + y^{2} - 20 x + x^{2} + 100

Solve

x^{2} = 2 x y - 20 y + y^{2} - 20 x + x^{2} + 100 : x = - \frac{y - 10}{2}

x = - \frac{y - 10}{2}

Verify Solutions:

x = - \frac{y - 10}{2} {y \leq 10}

The solution is

x = - \frac{y - 10}{2} {y \leq 10}

5 x - 39 - 7 = - 6

y, 2 x^{2} = - 2 y

19 - 2 x = x + 8

4 x^{2} - 4 x + 1 = 3

\frac{2000 ( 0.8 )}{x ^{0.2}} = 1500

What is the answer to solvefor x,sqrt(x^2)+x+y=10 ?
The answer to solvefor x,sqrt(x^2)+x+y=10 is x=-(y-10)/2 {y<= 10}