What is the answer to sqrt(x^2-x+1)=1 ?

The answer to sqrt(x^2-x+1)=1 is x=1,x=0

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sqrt(x^2-x+1)=1

x^{2} - x + 1 = 1

x = 1, x = 0

Solution steps

x^{2} - x + 1 = 1

Square both sides:

x^{2} - x + 1 = 1

x^{2} - x + 1 = 1

Solve

x^{2} - x + 1 = 1 : x = 1, x = 0

x = 1, x = 0

Verify Solutions:

x = 1

True

, x = 0

True

The solutions are

x = 1, x = 0

2 x + 1 + x - 1 = 4

5 = 10 (0.55)^{0.2} K^{0.4}

3 = 3 x^{3} + 2 x^{2} + 3 x + 1

2 x + 1 + x - 1 = 1

2 = x^{\frac{5}{3}}

What is the answer to sqrt(x^2-x+1)=1 ?
The answer to sqrt(x^2-x+1)=1 is x=1,x=0
Solve for x: sqrt(x^2-x+1)=1
The solution is x=1,x=0