Solution
Solution
+1
Decimal Notation
Solution steps
Remove square roots
Solve
Verify Solutions:FalseTrue
The solution is
Popular Examples
5=10(0.55)^{0.2}K^{0.4}3=sqrt(3x^3+2x^2+3x+1)sqrt(2x+1)+sqrt(x-1)=12=x^{5/3}x^2+3x-sqrt(x^2+3x-1)-7=0
Frequently Asked Questions (FAQ)
What is the answer to sqrt(2x+1)+sqrt(x-1)=4 ?
The answer to sqrt(2x+1)+sqrt(x-1)=4 is x=2(23-4sqrt(29))Solve for x: sqrt(2x+1)+sqrt(x-1)=4
The solution is x=2(23-4sqrt(29))