What is the answer to 1x=xsqrt((16^2-x^2)) ?

The answer to 1x=xsqrt((16^2-x^2)) is x=0,x=sqrt(255),x=-sqrt(255)

Solve for x: 1x=xsqrt((16^2-x^2))

The solution is x=0,x=sqrt(255),x=-sqrt(255)

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1 x = x (1 6^{2} - x^{2})

x = 0, x = 255, x = - 255

Decimal Notation

x = 0, x = 15.96871 \dots, x = - 15.96871 \dots

Solution steps

1 \cdot x = x (1 6^{2} - x^{2})

Move

x 1 6^{2} - x^{2}

to the left side

x - 1 6^{2} - x^{2} x = 0

Factor

x - 1 6^{2} - x^{2} x : - x (1 6^{2} - x^{2} - 1)

- x (1 6^{2} - x^{2} - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 1 6^{2} - x^{2} - 1 = 0

Solve

1 6^{2} - x^{2} - 1 = 0 : x = 255, x = - 255

x = 0, x = 255, x = - 255

Verify Solutions:

x = 0

True

, x = 255

True

, x = - 255

True

The solutions are

x = 0, x = 255, x = - 255

y, x = 3 y - 4

2 w + 18 + 1 = 5

- x + 5 = x + 1

1 = 3 x + 18 - 2

4 x - 3 = 2 + 2 x + 5

What is the answer to 1x=xsqrt((16^2-x^2)) ?
The answer to 1x=xsqrt((16^2-x^2)) is x=0,x=sqrt(255),x=-sqrt(255)
Solve for x: 1x=xsqrt((16^2-x^2))
The solution is x=0,x=sqrt(255),x=-sqrt(255)