What is the answer to 4x=40-4(sqrt(68-x^2)) ?

The answer to 4x=40-4(sqrt(68-x^2)) is x=8,x=2

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4x=40-4(sqrt(68-x^2))

4 x = 40 - 4 (68 - x^{2})

x = 8, x = 2

Solution steps

4 x = 40 - 4 (68 - x^{2})

Remove square roots

16 x^{2} - 320 x + 1600 = 1088 - 16 x^{2}

Solve

16 x^{2} - 320 x + 1600 = 1088 - 16 x^{2} : x = 8, x = 2

x = 8, x = 2

Verify Solutions:

x = 8

True

, x = 2

True

The solutions are

x = 8, x = 2

1 + (x - 2)^{\frac{2}{3}} = 0

10 x + 100 + 10 = x

X = \frac{13}{2}

What is the answer to 4x=40-4(sqrt(68-x^2)) ?
The answer to 4x=40-4(sqrt(68-x^2)) is x=8,x=2
Solve for x: 4x=40-4(sqrt(68-x^2))
The solution is x=8,x=2