What is the answer to solvefor q,f=\sqrt[4]{4q+11} ?

The answer to solvefor q,f=\sqrt[4]{4q+11} is q=(f^4-11)/4 {f>= 0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor q,f=\sqrt[4]{4q+11}

solve for

q = \frac{f ^{4} - 11}{4} {f \geq 0}

Solution steps

Take both sides of the equation to the power of

4 : f^{4} = 4 q + 11

f^{4} = 4 q + 11

Solve

f^{4} = 4 q + 11 : q = \frac{f ^{4} - 11}{4}

q = \frac{f ^{4} - 11}{4}

Verify Solutions:

q = \frac{f ^{4} - 11}{4} {f \geq 0}

The solution is

q = \frac{f ^{4} - 11}{4} {f \geq 0}

2 x + 1 = 9

p + 6 = 12

3 x + 7 - 3 = x - 2

x + 2 x - 10 = 9

x, g (2 x) = 2 x

What is the answer to solvefor q,f=\sqrt[4]{4q+11} ?
The answer to solvefor q,f=\sqrt[4]{4q+11} is q=(f^4-11)/4 {f>= 0}