What are the solutions to the equation 5x^2+6x-32=0 ?

The solutions to the equation 5x^2+6x-32=0 are x=2,x=-16/5

Find the zeros of 5x^2+6x-32=0

The zeros of 5x^2+6x-32=0 are x=2,x=-16/5

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5 x^{2} + 6 x - 32 = 0

x = 2, x = - \frac{16}{5}

Solution steps

5 x^{2} + 6 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 32 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 32) = 26

x_{1, 2} = \frac{- 6 \pm 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 26}{2 \cdot 5}, x_{2} = \frac{- 6 - 26}{2 \cdot 5}

x = \frac{- 6 + 26}{2 \cdot 5} : 2

x = \frac{- 6 - 26}{2 \cdot 5} : - \frac{16}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{16}{5}

(2 x + 1) (x - 2) (3 x - 4) \leq 0

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2 x^{2} - 4 x y + 2 y^{2}

\frac{i - 2}{i - 1}

x y + 7 y - 3 x - 21

What are the solutions to the equation 5x^2+6x-32=0 ?
The solutions to the equation 5x^2+6x-32=0 are x=2,x=-16/5
Find the zeros of 5x^2+6x-32=0
The zeros of 5x^2+6x-32=0 are x=2,x=-16/5