What is the answer to \sqrt[4]{x^2}+x-1-1=0 ?

The answer to \sqrt[4]{x^2}+x-1-1=0 is x=1

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\sqrt[4]{x^2}+x-1-1=0

x = 1

Solution steps

Expand

Remove roots

x^{2} = x^{4} - 8 x^{3} + 24 x^{2} - 32 x + 16

Solve

x^{2} = x^{4} - 8 x^{3} + 24 x^{2} - 32 x + 16 : x = 1, x = 4

x = 1, x = 4

Verify Solutions:

x = 1

True

, x = 4

False

The solution is

x = 1

x + 8 x - 47 = 7

2 p + 7 - p + 9 = 0

\frac{1}{1 - x ^{2}} = 2.5

5 x + 24 = 3 x - 16

What is the answer to \sqrt[4]{x^2}+x-1-1=0 ?
The answer to \sqrt[4]{x^2}+x-1-1=0 is x=1
Solve for x: \sqrt[4]{x^2}+x-1-1=0
The solution is x=1