What is the answer to sqrt(2x^2-5x+3)=0 ?

The answer to sqrt(2x^2-5x+3)=0 is x= 3/2 ,x=1

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sqrt(2x^2-5x+3)=0

2 x^{2} - 5 x + 3 = 0

x = \frac{3}{2}, x = 1

Decimal Notation

x = 1.5, x = 1

Solution steps

2 x^{2} - 5 x + 3 = 0

Square both sides:

2 x^{2} - 5 x + 3 = 0

2 x^{2} - 5 x + 3 = 0

Solve

2 x^{2} - 5 x + 3 = 0 : x = \frac{3}{2}, x = 1

x = \frac{3}{2}, x = 1

Verify Solutions:

x = \frac{3}{2}

True

, x = 1

True

The solutions are

x = \frac{3}{2}, x = 1

1.6 = \frac{( 171 ) ( w )}{60}

65 = 48 (t)^{\frac{1}{5}}

x^{(\frac{1}{4})} = 8.856161671

2 x + 9 - (3 - 2 x) = 0

1 = x \cdot x^{2} + x^{2} - x

What is the answer to sqrt(2x^2-5x+3)=0 ?
The answer to sqrt(2x^2-5x+3)=0 is x= 3/2 ,x=1
Solve for x: sqrt(2x^2-5x+3)=0
The solution is x= 3/2 ,x=1