What is the answer to 2-\sqrt[3]{x^2+2x}=0 ?

The answer to 2-\sqrt[3]{x^2+2x}=0 is x=-4,x=2

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2-\sqrt[3]{x^2+2x}=0

x = - 4, x = 2

Solution steps

Move

2

to the right side

Take both sides of the equation to the power of

3 : - x^{2} - 2 x = - 8

- x^{2} - 2 x = - 8

Solve

- x^{2} - 2 x = - 8 : x = - 4, x = 2

x = - 4, x = 2

Verify Solutions:

x = - 4

True

, x = 2

True

The solutions are

x = - 4, x = 2

4 = x - 6

x^{2} + (3 x)^{2} = 8

x = x - 1

5 x^{2} = 8 x

\frac{5}{x - 4} - 2 x - 4 + 3 = 0

What is the answer to 2-\sqrt[3]{x^2+2x}=0 ?
The answer to 2-\sqrt[3]{x^2+2x}=0 is x=-4,x=2
Solve for x: 2-\sqrt[3]{x^2+2x}=0
The solution is x=-4,x=2