What is the answer to 4=sqrt(x^2+\sqrt{3^2)} ?

The answer to 4=sqrt(x^2+\sqrt{3^2)} is x=sqrt(13),x=-sqrt(13)

Solve for x: 4=sqrt(x^2+\sqrt{3^2)}

The solution is x=sqrt(13),x=-sqrt(13)

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4 = x^{2} + 3^{2}

x = 13, x = - 13

Decimal Notation

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

4 = x^{2} + 3^{2}

Square both sides:

16 = x^{2} + 3

16 = x^{2} + 3

Solve

16 = x^{2} + 3 : x = 13, x = - 13

x = 13, x = - 13

Verify Solutions:

x = 13

True

, x = - 13

True

The solutions are

x = 13, x = - 13

15 = 3 l

(3 + x)^{2} = 2

y, x = y + 4

v, 2 v = t

v = 9

What is the answer to 4=sqrt(x^2+\sqrt{3^2)} ?
The answer to 4=sqrt(x^2+\sqrt{3^2)} is x=sqrt(13),x=-sqrt(13)
Solve for x: 4=sqrt(x^2+\sqrt{3^2)}
The solution is x=sqrt(13),x=-sqrt(13)