What is the answer to solvefor x,2sqrt(x-8)=7y^2 ?

The answer to solvefor x,2sqrt(x-8)=7y^2 is x=(49y^4)/4+8

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solvefor x,2sqrt(x-8)=7y^2

solve for

x, 2 x - 8 = 7 y^{2}

x = \frac{49 y ^{4}}{4} + 8

Solution steps

2 x - 8 = 7 y^{2}

Divide both sides by

2

x - 8 = \frac{7 y ^{2}}{2}

Square both sides:

x - 8 = \frac{49 y ^{4}}{4}

x - 8 = \frac{49 y ^{4}}{4}

Solve

x - 8 = \frac{49 y ^{4}}{4} : x = \frac{49 y ^{4}}{4} + 8

x = \frac{49 y ^{4}}{4} + 8

Verify Solutions:

x = \frac{49 y ^{4}}{4} + 8

True

The solution is

x = \frac{49 y ^{4}}{4} + 8

x - 6 = 9

3 x^{2} + 6 x - 15 = 0

2 x^{2} + 3 x - 1 = 5 - x

15 x = 5 x

0 = 96 q - 4 q^{\frac{3}{2}}

What is the answer to solvefor x,2sqrt(x-8)=7y^2 ?
The answer to solvefor x,2sqrt(x-8)=7y^2 is x=(49y^4)/4+8