What are the solutions to the equation -4p^2+8000p=0 ?

The solutions to the equation -4p^2+8000p=0 are p=0,p=2000

Find the zeros of -4p^2+8000p=0

The zeros of -4p^2+8000p=0 are p=0,p=2000

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- 4 p^{2} + 8000 p = 0

p = 0, p = 2000

Solution steps

- 4 p^{2} + 8000 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8000 \pm 800 0 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

800 0^{2} - 4 (- 4) \cdot 0 = 8000

p_{1, 2} = \frac{- 8000 \pm 8000}{2 ( - 4 )}

Separate the solutions

p_{1} = \frac{- 8000 + 8000}{2 ( - 4 )}, p_{2} = \frac{- 8000 - 8000}{2 ( - 4 )}

p = \frac{- 8000 + 8000}{2 ( - 4 )} : 0

p = \frac{- 8000 - 8000}{2 ( - 4 )} : 2000

The solutions to the quadratic equation are:

p = 0, p = 2000

\frac{( 2 x ^{2} y ^{0} ) ^{3}}{x ^{3}}

x^{2} - 9 x + 20 \geq 0

- 2 x + 3 = - 5

x (2 x - 11) = - 12

se gu n d a (t^{2} - 4)^{\frac{2}{3}}

What are the solutions to the equation -4p^2+8000p=0 ?
The solutions to the equation -4p^2+8000p=0 are p=0,p=2000
Find the zeros of -4p^2+8000p=0
The zeros of -4p^2+8000p=0 are p=0,p=2000