What are the solutions to the equation x(2x-11)=-12 ?

The solutions to the equation x(2x-11)=-12 are x=4,x= 3/2

Find the zeros of x(2x-11)=-12

The zeros of x(2x-11)=-12 are x=4,x= 3/2

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x (2 x - 11) = - 12

x = 4, x = \frac{3}{2}

Solution steps

x (2 x - 11) = - 12

Expand

x (2 x - 11) : 2 x^{2} - 11 x

2 x^{2} - 11 x = - 12

Move

12

to the left side

2 x^{2} - 11 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 12 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 2}

x = \frac{- ( - 11 ) + 5}{2 \cdot 2} : 4

x = \frac{- ( - 11 ) - 5}{2 \cdot 2} : \frac{3}{2}

The solutions to the quadratic equation are:

x = 4, x = \frac{3}{2}

se gu n d a (t^{2} - 4)^{\frac{2}{3}}

5 k^{- 3}

3 t^{2} - 27 = 0

- 5 - 2 (x - 5) = - (x + 3)

- \frac{π}{6} - π

What are the solutions to the equation x(2x-11)=-12 ?
The solutions to the equation x(2x-11)=-12 are x=4,x= 3/2
Find the zeros of x(2x-11)=-12
The zeros of x(2x-11)=-12 are x=4,x= 3/2