What is the answer to sqrt((-x)^2+x^2)=1 ?

The answer to sqrt((-x)^2+x^2)=1 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: sqrt((-x)^2+x^2)=1

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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(- x)^{2} + x^{2} = 1

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

(- x)^{2} + x^{2} = 1

Square both sides:

2 x^{2} = 1

2 x^{2} = 1

Solve

2 x^{2} = 1 : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}

11 x - 1 = 5 + 7 x - 1

x, x = 2 E + 12

x - 2 = 2 - x

4 - x^{2} = \frac{( 4 - x )}{2}

0.5 x - x^{0.5} = 0

What is the answer to sqrt((-x)^2+x^2)=1 ?
The answer to sqrt((-x)^2+x^2)=1 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: sqrt((-x)^2+x^2)=1
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))