What are the solutions to the equation 64x^2+80x+25=0 ?

The solutions to the equation 64x^2+80x+25=0 are x=-5/8

Find the zeros of 64x^2+80x+25=0

The zeros of 64x^2+80x+25=0 are x=-5/8

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64 x^{2} + 80 x + 25 = 0

x = - \frac{5}{8}

Solution steps

64 x^{2} + 80 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 64 \cdot 25}{2 \cdot 64}

8 0^{2} - 4 \cdot 64 \cdot 25 = 0

x_{1, 2} = \frac{- 80 \pm 0}{2 \cdot 64}

x = \frac{- 80}{2 \cdot 64}

\frac{- 80}{2 \cdot 64} = - \frac{5}{8}

x = - \frac{5}{8}

The solution to the quadratic equation is:

x = - \frac{5}{8}

\frac{a}{( \frac{b}{c} )}

\frac{3 π}{2}

(x - 9)^{2} = 144

(148)^{\frac{3}{2}}

ln (\frac{5}{3})

What are the solutions to the equation 64x^2+80x+25=0 ?
The solutions to the equation 64x^2+80x+25=0 are x=-5/8
Find the zeros of 64x^2+80x+25=0
The zeros of 64x^2+80x+25=0 are x=-5/8