What are the solutions to the equation 2x^2-17x+21=0 ?

The solutions to the equation 2x^2-17x+21=0 are x=7,x= 3/2

Find the zeros of 2x^2-17x+21=0

The zeros of 2x^2-17x+21=0 are x=7,x= 3/2

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2 x^{2} - 17 x + 21 = 0

x = 7, x = \frac{3}{2}

Solution steps

2 x^{2} - 17 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 21}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 21 = 11

x_{1, 2} = \frac{- ( - 17 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 11}{2 \cdot 2}

x = \frac{- ( - 17 ) + 11}{2 \cdot 2} : 7

x = \frac{- ( - 17 ) - 11}{2 \cdot 2} : \frac{3}{2}

The solutions to the quadratic equation are:

x = 7, x = \frac{3}{2}

- 5 = - 1 + a

x^{3} + 11 x \leq 6 x^{2} + 6

4 x^{2} - 8 x = 40

25 x^{2} + 20 x + 4 = 0

12 = 6 y - 36

What are the solutions to the equation 2x^2-17x+21=0 ?
The solutions to the equation 2x^2-17x+21=0 are x=7,x= 3/2
Find the zeros of 2x^2-17x+21=0
The zeros of 2x^2-17x+21=0 are x=7,x= 3/2