What are the solutions to the equation y^2+20y-9=0 ?

The solutions to the equation y^2+20y-9=0 are y=-10+sqrt(109),y=-10-sqrt(109)

Find the zeros of y^2+20y-9=0

The zeros of y^2+20y-9=0 are y=-10+sqrt(109),y=-10-sqrt(109)

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y^{2} + 20 y - 9 = 0

y = - 10 + 109, y = - 10 - 109

Solution steps

y^{2} + 20 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 9) = 2109

y_{1, 2} = \frac{- 20 \pm 2 109}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 20 + 2 109}{2 \cdot 1}, y_{2} = \frac{- 20 - 2 109}{2 \cdot 1}

y = \frac{- 20 + 2 109}{2 \cdot 1} : - 10 + 109

y = \frac{- 20 - 2 109}{2 \cdot 1} : - 10 - 109

The solutions to the quadratic equation are:

y = - 10 + 109, y = - 10 - 109

9 x + 4 = 7 x + 4

x = 5 (90 - x)

2 x^{2} + 3 x = 65

\frac{3}{2} (1)

(6 - 7 i) + (8 + 4 i)

What are the solutions to the equation y^2+20y-9=0 ?
The solutions to the equation y^2+20y-9=0 are y=-10+sqrt(109),y=-10-sqrt(109)
Find the zeros of y^2+20y-9=0
The zeros of y^2+20y-9=0 are y=-10+sqrt(109),y=-10-sqrt(109)