What are the solutions to the equation 2x^2+3x=65 ?

The solutions to the equation 2x^2+3x=65 are x=5,x=-13/2

Find the zeros of 2x^2+3x=65

The zeros of 2x^2+3x=65 are x=5,x=-13/2

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2 x^{2} + 3 x = 65

x = 5, x = - \frac{13}{2}

Decimal Notation

x = 5, x = - 6.5

Solution steps

2 x^{2} + 3 x = 65

Move

65

to the left side

2 x^{2} + 3 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 65 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 65) = 23

x_{1, 2} = \frac{- 3 \pm 23}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 23}{2 \cdot 2}, x_{2} = \frac{- 3 - 23}{2 \cdot 2}

x = \frac{- 3 + 23}{2 \cdot 2} : 5

x = \frac{- 3 - 23}{2 \cdot 2} : - \frac{13}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{13}{2}

\frac{3}{2} (1)

(6 - 7 i) + (8 + 4 i)

- \frac{\frac{1}{2}}{- \frac{3}{2}}

\frac{k ^{9}}{k ^{5}}

64 x^{2} y^{3} + x y^{2}

What are the solutions to the equation 2x^2+3x=65 ?
The solutions to the equation 2x^2+3x=65 are x=5,x=-13/2
Find the zeros of 2x^2+3x=65
The zeros of 2x^2+3x=65 are x=5,x=-13/2