What is (6-7i)+(8+4i) ?

The solution to (6-7i)+(8+4i) is 14-3i

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simplify (6-7i)+(8+4i)

simplify

(6 - 7 i) + (8 + 4 i)

14 - 3 i

Solution steps

(6 - 7 i) + (8 + 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (6 + 8) + (- 7 + 4) i

Simplify

(6 + 8) + (- 7 + 4) i : 14 - 3 i

= 14 - 3 i

- \frac{\frac{1}{2}}{- \frac{3}{2}}

\frac{k ^{9}}{k ^{5}}

64 x^{2} y^{3} + x y^{2}

a^{4} + a b^{3} - a^{3} b - b^{4}

17 \cdot 6