What are the solutions to the equation 2k^2+74k=0 ?

The solutions to the equation 2k^2+74k=0 are k=0,k=-37

Find the zeros of 2k^2+74k=0

The zeros of 2k^2+74k=0 are k=0,k=-37

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2 k^{2} + 74 k = 0

k = 0, k = - 37

Solution steps

2 k^{2} + 74 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 74 \pm 7 4 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

7 4^{2} - 4 \cdot 2 \cdot 0 = 74

k_{1, 2} = \frac{- 74 \pm 74}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 74 + 74}{2 \cdot 2}, k_{2} = \frac{- 74 - 74}{2 \cdot 2}

k = \frac{- 74 + 74}{2 \cdot 2} : 0

k = \frac{- 74 - 74}{2 \cdot 2} : - 37

The solutions to the quadratic equation are:

k = 0, k = - 37

- 3 x + 6 = 0

\frac{4 x ^{2} - 1}{4 x ^{2} + 8 x + 3} \leq 0

\frac{5 x}{4 - 2 x} \geq \frac{1 + x}{x - 2}

(2 x^{4})^{3}

What are the solutions to the equation 2k^2+74k=0 ?
The solutions to the equation 2k^2+74k=0 are k=0,k=-37
Find the zeros of 2k^2+74k=0
The zeros of 2k^2+74k=0 are k=0,k=-37