What are the solutions to the equation 3x(5-x)=2 ?

The solutions to the equation 3x(5-x)=2 are x=(15-sqrt(201))/6 ,x=(15+sqrt(201))/6

Find the zeros of 3x(5-x)=2

The zeros of 3x(5-x)=2 are x=(15-sqrt(201))/6 ,x=(15+sqrt(201))/6

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3 x (5 - x) = 2

x = \frac{15 - 201}{6}, x = \frac{15 + 201}{6}

Decimal Notation

x = 0.13709 \dots, x = 4.86290 \dots

Solution steps

3 x (5 - x) = 2

Expand

3 x (5 - x) : 15 x - 3 x^{2}

15 x - 3 x^{2} = 2

Move

2

to the left side

15 x - 3 x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 15 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

1 5^{2} - 4 (- 3) (- 2) = 201

x_{1, 2} = \frac{- 15 \pm 201}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 15 + 201}{2 ( - 3 )}, x_{2} = \frac{- 15 - 201}{2 ( - 3 )}

x = \frac{- 15 + 201}{2 ( - 3 )} : \frac{15 - 201}{6}

x = \frac{- 15 - 201}{2 ( - 3 )} : \frac{15 + 201}{6}

The solutions to the quadratic equation are:

x = \frac{15 - 201}{6}, x = \frac{15 + 201}{6}

(\frac{1 2 ^{- 4}}{3 ^{2}})^{2} (\frac{5}{2})^{- 2}

(- a^{3} b)^{4}

2 \cdot 23

lo g_{a} (\frac{( - 2 a b ^{2} ) ^{- 3}}{a ^{2} b ^{- 4}})

4 x - 3 = 5

What are the solutions to the equation 3x(5-x)=2 ?
The solutions to the equation 3x(5-x)=2 are x=(15-sqrt(201))/6 ,x=(15+sqrt(201))/6
Find the zeros of 3x(5-x)=2
The zeros of 3x(5-x)=2 are x=(15-sqrt(201))/6 ,x=(15+sqrt(201))/6