What are the solutions to the equation x^2+12x+42=0 ?

The solutions to the equation x^2+12x+42=0 are x=-6+sqrt(6)i,x=-6-sqrt(6)i

Find the zeros of x^2+12x+42=0

The zeros of x^2+12x+42=0 are x=-6+sqrt(6)i,x=-6-sqrt(6)i

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x^{2} + 12 x + 42 = 0

x = - 6 + 6 i, x = - 6 - 6 i

Solution steps

x^{2} + 12 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 42 : 26 i

x_{1, 2} = \frac{- 12 \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 6 i}{2 \cdot 1}

x = \frac{- 12 + 2 6 i}{2 \cdot 1} : - 6 + 6 i

x = \frac{- 12 - 2 6 i}{2 \cdot 1} : - 6 - 6 i

The solutions to the quadratic equation are:

x = - 6 + 6 i, x = - 6 - 6 i

64 x^{2} - 25 = 0

\frac{3}{4} + \frac{7}{8}

x^{2} + 45 x + 200 = 0

1 > - 5 - a

\frac{n ^{2}}{( n + 1 ) ^{2}}

What are the solutions to the equation x^2+12x+42=0 ?
The solutions to the equation x^2+12x+42=0 are x=-6+sqrt(6)i,x=-6-sqrt(6)i
Find the zeros of x^2+12x+42=0
The zeros of x^2+12x+42=0 are x=-6+sqrt(6)i,x=-6-sqrt(6)i